Foundation June 2024 Paper 1 Q8
8
(a) Simplify \(\quad 10x - 7y - 6x + 4y\) (2)
\(T = 4d - 6e\)
(b) Work out the value of \(T\) when \(d = 13\) and \(e = 7\) (2)
(c) Solve \(\quad 5p + 11 = 28\) (2)
| Scheme | Marks |
|---|---|
| \(4x - 3y\) | B2 |
| (2) |
Notes
B2: Accept \(-3y + 4x\)
(If not B2 then award
B1 for \(4x\) or \(-3y\))
| Scheme | Marks |
|---|---|
| 4 × 13 and ±6 × 7 or 52 and ±42 | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: 10 | A1 |
| (2) |
Notes
A1: SC B1 for –50
| Scheme | Marks |
|---|---|
\(5p = 28 - 11\) or \(11 - 28 = -5p\) or \(5p = 17\) or \(p + \dfrac{11}{5} = \dfrac{28}{5}\) or (28 – 11) ÷ 5 oe | M1 |
Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: \(\dfrac{17}{5}\) | A1 |
| (2) | |
| (6 marks) |
Notes
A1: oe e.g. 3.4 or \(3\dfrac{2}{5}\)