Foundation June 2023 Paper 2 Q19
19 \(ABCD\) is a trapezium.
Diagram NOT accurately drawn
\(BC\) is parallel to \(AD\)
Find the size of the largest angle inside the trapezium.
(4)
| Scheme | Marks |
|---|---|
| \((4x - 27) + (3x + 46) = 180\) oe or \(\text{``}{\text{expression for C}}\text{''} + (3x + 10) = 180\) or \(7x + 19 = 180\) or \(3x + 46 + 4x - 27 + 3x + 10 + [\text{``}{180 - (3x + 10)}\text{''}] = 360\) | M1 |
| A1 | |
| eg \(3 \times \text{``}{23}\text{''} + 46\) (= 115) or eg \(180 - (3 \times \text{``}{23}\text{''} + 10)\) (= 101) | M1ft |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 115 | A1 |
| (4) | |
| (4 marks) |
Notes
M1: Sum angles \(A\) and \(B\) to 180, or find an expression for \(BCD\) and sum all angles to 360.
[condone missing brackets and condone use of any letter for angle \(C\) (even \(x\) or \(BCD\))]
A1: \(x = 23\)
M1ft: dep on M1
using their \(x\) to calculate a value for angle \(B\) or \(C\) (cannot be a negative value and cannot just be \(x\))
A1: Allow \(3x + 46\) or \(ABC\) if 115 is clearly seen in working or on diagram