Foundation June 2022 Paper 2 Q9
9 3 cups each contain 200 millilitres of water.
4 jugs each contain \(x\) millilitres of water.
Emma pours all the water from the 3 cups and the 4 jugs into a container.
The total amount of water that Emma pours into the container from the 3 cups and 4 jugs is 3.5 litres.
Work out the value of \(x\)
(4)
| Scheme | Marks |
|---|---|
| 200 (m\(l\)) written as 0.2 (\(l\)) or 3.5 (\(l\)) written as 3500 (m\(l\)) | B1 |
| 3 × “0.2” (= 0.6) oe eg 0.2 + 0.2 + 0.2 or 3 × 200 (= 600) oe eg –200–200–200 or 3500 – 600 (= 2900) | M1 |
| \(\dfrac{3.5 - \text{``}{0.6}\text{''}}{4}\) or \(\dfrac{\text{``}{3500}\text{''} - \text{``}{600}\text{''}}{4}\) oe | M1 |
| 725 | A1 |
| (4) | |
| (4 marks) |
Notes
B1: for a correct conversion
M1: A correct calculation for the total amount of water in the 3 cups or the 4 jugs
M1: For a fully correct method or for an answer of 0.725 (this alone gains B1M2)
A1: (SCB1M1 (no other marks) for
(3.5 – 0.2) ÷ 4 (= 0.825) or
(3500 – 200) ÷ 4 (= 825))