Foundation June 2021 Paper 1 Q7
7 The diagram shows a rectangle and a square.
Diagram NOT accurately drawn
The perimeter of the rectangle is equal to the perimeter of the square.
The area of the rectangle is less than the area of the square.
Work out by how much the area of the rectangle is less than the area of the square.
(4)
| Scheme | Marks |
|---|---|
| [perimeter =] 10 + 6 + 10 + 6 (= 32) or (10 + 6) × 2 (= 32) or 10 + 6 (= 16) | M1 |
| [area =] 10 × 6 (= 60) | M1 |
| \((\text{“}32\text{”} \div 4)^2 - \text{‘}60\text{’}\) or \((\text{“}16\text{”} \div 2)^2 - \text{‘}60\text{’}\) | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working eg a wrong conversion) Answer: 4 | A1 |
| (4) | |
| (4 marks) |
Notes
M1: for perimeter or semi perimeter of rectangle
M1: (indep) for area of rectangle
M1: for a completely correct method
Allow 60 – area of square