Foundation January 2023 Paper 2 Q17
17 Change a speed of 90 kilometres per hour to a speed in metres per second.
Show your working clearly.
(3)
| Scheme | Marks |
|---|---|
90 × 1000 (= 90 000) or \(\dfrac{90}{60 \times 60}\left(= 0.025 \text{ or } \dfrac{1}{40}\right)\) or \(\dfrac{1000}{60 \times 60}\left(= \dfrac{5}{18} = 0.277...\right)\) or sight of 1500 | M1 |
| \(\dfrac{90 \times 1000}{60 \times 60}\) oe eg(1.5 × 1000) ÷ 60 | M1 |
| Working required Answer: 25 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: For one of ×1000 (eg sight of 90 000) or (÷60 ÷ 60) or ÷3600 oe
ie correct conversion of distance units or of time units
M1: For a fully correct method with correct use of brackets
eg 90 000 ÷ 60 × 60 is M1 only if not recovered
A1: dep on M1
M2 for 90 ÷ 3.6 or \(90 \times \dfrac{5}{18}\)