Foundation January 2022 Paper 1 Q14
14 On the grid, draw the graph of \(y = 2x - 3\) for values of \(x\) from \(-2\) to 4
(3)
| Scheme | Marks |
|---|---|
| \((-2, -7)\), \((-1, -5)\), \((0, -3)\), \((1, -1)\), \((2, 1)\), \((3, 3)\), \((4, 5)\) Answer: line \(y = 2x - 3\) drawn | B3 |
| (3) | |
| (3 marks) |
Notes
B3: For a correct line between \(x = -2\) and \(x = 4\)
(B2 for a straight line segment through at least 3 of the given points OR for all of the points plotted and not joined OR for a line drawn through \((0, -3)\) with a clear attempt at a gradient of 2 (eg a line through \((0, -3)\) and \((1, -1)\)))
(B1 for at least 2 correct points stated or plotted (may be in table); ignore any incorrect points either plotted or evaluated OR for a line drawn with positive gradient through \((0, -3)\) OR for a straight line with gradient 2)