Foundation January 2019 Paper 2 Q19
19 Calvin has 12 identical rectangular tiles.
He arranges the tiles to fit exactly round the edge of a shaded rectangle, as shown in the diagram below.
Diagram NOT accurately drawn
Work out the area of the shaded rectangle.
(5)
| Scheme | Marks |
|---|---|
| 123 – 67 (= 56) or \(2x = 123 - 67\) or \(2x + y = 67\) or \(4x + y = 123\) oe (\(x\) = length of tile, \(y\) = width of tile) | M1 |
| e.g. “56” ÷ 2 (= 28) | M1 |
| 67 – 56 (= 11) or 67 – 2 × “28” (= 11) or 123 – 4 × “28” (= 11) | M1 |
| (67 – 2 × “11”) × (123 – 2 × “11”) (45 × 101) or 123 × 67 – 12 × “28” × “11” (8241 – 3696) | M1 |
| 4545 | A1 |
| (5) | |
| (5 marks) |
Notes
M1: for method to find length or width
M1: for method to find other dimension
M1: dep on M2