Foundation January 2019 Paper 1R Q10
10 There are 20 beads in a box.
7 of the beads are red.
11 of the beads are green.
The rest of the beads are yellow.
Jan takes at random a bead from the box.
There are 26 counters in a bag.
5 of the counters are pink.
10 of the counters are blue.
The rest of the counters are white.
Jan puts some more pink counters into the bag.
She then takes some blue counters out of the bag.
After she has done this there are still 26 counters in the bag.
Jan then takes at random a counter from the bag.
The probability that she takes a pink counter is \(\dfrac{1}{2}\)
| Scheme | Marks |
|---|---|
| \(\dfrac{7}{20}\) | B1 |
| (1) |
Notes
B1: oe
| Scheme | Marks |
|---|---|
| 20 − 7 − 11 (= 2) and “2” + 7 (= 9) OR 20 – 11 (= 9) | M1 |
| \(\dfrac{9}{20}\) | A1 |
| (2) |
Notes
M1: for a complete method to find the number of beads that are either red or yellow- may be seen in probabilities
A1: oe
| Scheme | Marks |
|---|---|
| eg \(\dfrac{1}{2} \times 26\) (= 13) | M1 |
| eg 10 − (“13” − 5) (= 2) or 26 – (26 – 10 – 5) – “13” (= 2) | M1 |
| \(\dfrac{2}{26}\) | A1 |
| (3) | |
| (6 marks) |
Notes
M1: for a method to calculate the number of pink counters
M1: for a complete method to find the final number of blue counters
A1: oe