Higher November 2023 Paper 2 Q16
16 \(ABCD\) is a trapezium.
\(AD\) is parallel to \(BC\).
Calculate the area of triangle \(BCD\).
Give your answer correct to 1 decimal place. (4)
| Answer | Mark | Mark scheme |
|---|---|---|
| 56.0 | P1 | for \(\dfrac{BD}{\sin(112)} = \dfrac{7.9}{\sin(42)}\) |
| P1 | for complete process to find \(BD\), eg \((BD =)\ \dfrac{7.9}{\sin(42)} \times \sin(112)\ (= 10.9\ldots)\) | |
| P1 | for area \(= \dfrac{1}{2} \times [BD] \times 15.3 \times \sin(42)\) | |
| A1 | for answer in the range 56.0 to 56.1 SCB2 for \(BD = 10.9\ldots\) if no marks are awarded. |
Additional guidance
Values may be rounded or truncated.
\([BD]\) must be clearly identified
If an answer is given in the range in working and then rounded incorrectly award full marks.