Higher November 2018 Paper 1 Q2
2 \(v^2 = u^2 + 2as\)
\(u = 12 \qquad a = -3 \qquad s = 18\)
(a) Work out a value of \(v\). (2)
(b) Make \(s\) the subject of \(v^2 = u^2 + 2as\) (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| 6 or \(-6\) | M1 | for \(12^2 + 2 \times -3 \times 18\ (= 36)\) |
| A1 | for 6 or \(-6\), accept \(\pm 6\) |
Additional guidance
Terms may be partially evaluated.
Only one value is required for full marks
| Answer | Mark | Mark scheme |
|---|---|---|
| \(s = \dfrac{v^2 - u^2}{2a}\) | M1 | for subtracting \(u^2\) from both sides or dividing all terms by \(2a\) as the first step |
| A1 | \(s = \dfrac{v^2 - u^2}{2a}\) oe |
Additional guidance
Must see this step carried out, not just the intention shown