Higher November 2017 Paper 1 Q15
15 \(x = 0.4\dot{3}\dot{6}\)
Prove algebraically that \(x\) can be written as \(\dfrac{24}{55}\) (3)
| Answer | Mark | Notes |
|---|---|---|
| Proof to reach \(\dfrac{24}{55}\) | M1 | for \(100x = 43.636\ldots\ (43.\dot{6}\dot{3})\) or \(10x = 4.3636\ldots\ (4.\dot{3}\dot{6})\) and \(1000x = 436.36\ldots\ (436.\dot{3}\dot{6})\) |
| M1 | (dep) for finding difference that would lead to a terminating decimal | |
| A1 | for completing algebra to reach \(\dfrac{24}{55}\) |