Higher June 2025 Paper 2 Q19
19 \(ABCDEFGH\) is a cuboid.
Angle \(GEF = 52^\circ\)
Angle \(BHG = 27^\circ\)
\(EF = 15\) cm
Work out the size of angle \(GEB\).
Give your answer to the nearest degree. (4)
| Answer | Mark | Mark scheme |
|---|---|---|
| 17 | P1 | for a process to use trigonometry to find \(BG\) eg \(\dfrac{BG}{15} = \tan 27\) or 7.64(28…) |
| P1 | for a process to find to find \(EG\) eg \(\dfrac{15}{EG} = \cos 52\) or 24.3(64…) | |
| P1 | for a process to use trigonometry to find angle \(GEB\) eg \(\tan GEB = \dfrac{\text{``}7.64\ldots\text{''}}{\text{``}24.36\ldots\text{''}}\) | |
| A1 | for an answer in the range 17 to 17.6 |
Additional guidance
Other methods are possible for all P marks but only award the mark at the point of an equation with the correct length or angle as the only unknown