Higher June 2024 Paper 1 Q2
2
(a) Work out \(3\dfrac{4}{5} - 1\dfrac{2}{3}\) (2)
Kevin was asked to work out \(2\dfrac{1}{3} \times \dfrac{5}{8}\)
Here is his working and his answer.
\[\begin{aligned} 2\dfrac{1}{3} \times \dfrac{5}{8} &= \dfrac{7}{3} \times \dfrac{5}{8} \\[4pt] &= \dfrac{35}{24} \\[4pt] &= 1\dfrac{9}{24} \end{aligned}\]Kevin’s answer is wrong.
(b) What mistake has Kevin made? (1)
| Answer | Mark | Mark scheme |
|---|---|---|
| \(2\dfrac{2}{15}\) | M1 | for a method to subtract using a common denominator with at least one fraction correct (suitable common denominator for original fractions with at least one correct numerator) eg \(\dfrac{57}{15} - \dfrac{25}{15}\) or \((3)\dfrac{12}{15} - (1)\dfrac{10}{15}\) |
| A1 | for \(2\dfrac{2}{15}\) oe eg \(\dfrac{32}{15}\) |
Additional guidance
Use of decimals gets no credit unless it leads to a correct fraction
ISW incorrect conversion from improper fraction to mixed number or incorrect simplification of improper fraction
| Answer | Mark | Mark scheme |
|---|---|---|
| Mistake identified | C1 | for explaining that Kevin did not convert to the correct mixed number Acceptable examples In his answer \(\dfrac{9}{24}\) should have been \(\dfrac{11}{24}\) The 9 should be 11 He has not got the numerator right in his final answer He simplified into the mixed number incorrectly He has not put the remainder as the numerator \(1\dfrac{9}{24}\) would give you \(\dfrac{33}{24}\) rather than \(\dfrac{35}{24}\) \(\dfrac{35}{24} = 1\dfrac{11}{24}\) Not acceptable examples He should have used a common denominator He has not simplified his answer He should have done keep, flip, change He converted the fraction wrongly The answer should be \(1\dfrac{10}{24}\) |
Additional guidance
Figures may be seen in the question space