Higher June 2018 Paper 3 Q7
7 Solve \(\dfrac{5 - x}{2} = 2x - 7\) (3)
| Answer | Mark | Mark scheme |
|---|---|---|
| 3.8 | M1 | for a correct first step, eg \(5 - x = 2(2x - 7)\) or \(5 - x = 4x - 14\) or \(\dfrac{5}{2} - \dfrac{x}{2} = 2x - 7\) |
| M1 | (dep) for isolating terms in \(x\) eg \(4x + x = 14 + 5\) or \(-\dfrac{x}{2} - 2x = -7 - \dfrac{5}{2}\) | |
| A1 | oe |
Additional guidance
Method must show LHS \(\times 2\) and both terms on RHS \(\times 2\) or \(5 - x\) and both terms on RHS \(\times 2\)
eg \(-4x\) both sides with \(-5\) both sides
or \(+x\) both sides with \(+14\) both sides
Accept \(\dfrac{19}{5}\), \(3\dfrac{4}{5}\) oe but not \(\dfrac{-19}{-5}\) oe