Foundation June 2025 Paper 1 Q25
25 The straight line L is shown on the grid.
Find an equation for L.
Give your answer in the form \(y = mx + c\) (3)
| Answer | Mark | Mark scheme |
|---|---|---|
| \(y = -\dfrac{3}{4}x + 3\) | M1 | for a correct method to find the gradient of the line, eg \(\dfrac{3-0}{0-4}\ \left(= -\dfrac{3}{4}\right)\) or identifies 3 as the intercept in words or in a partial equation or for \(y = \left[-\dfrac{3}{4}\right]x + c\) or for \(y - b = \left[-\dfrac{3}{4}\right](x - a)\) where \((a, b)\) is a correct coordinate |
| M1 | for \(y = -\dfrac{3}{4}x\ (+\ c)\) oe or for \(y = \text{``}{-}\dfrac{3}{4}\text{''}x + 3\), \(m \neq 0\) or (L =) \(-\dfrac{3}{4}x + 3\) or \(y - y_1 = -\dfrac{3}{4}(x - x_1)\) or \(y - b = \text{``}{-}\dfrac{3}{4}\text{''}(x - a)\) where \((a, b)\) is a correct coordinate or for an answer of \(y = \dfrac{3}{4}x + 3\) oe | |
| A1 | for \(y = -\dfrac{3}{4}x + 3\) oe provided the equation in the required form |
Additional guidance
Just circling 3 is insufficient
\(\left[-\dfrac{3}{4}\right]\) must be identifiable as their gradient
\(c\) must be seen either as a letter or a number
Allow eg \(y = 3 - \dfrac{3}{4}x\)
A correct equation not in the required form scores M1M1A0