Foundation June 2023 Paper 2 Q24
24 Here is a triangle and a rectangle.
All measurements are in centimetres.
The area of the triangle is 10 cm\(^2\) greater than the area of the rectangle.
Work out the value of \(x\). (4)
| Answer | Mark | Mark scheme |
|---|---|---|
| 1.25 | P1 | for finding an expression for the area of one shape, eg \(\dfrac{1}{2} \times 8 \times 6x\ (= 24x)\) or \(5(4x - 1)\ (= 20x - 5)\) oe |
| P1 | for finding an expression for the area of both shapes, eg \(\dfrac{1}{2} \times 8 \times 6x\) and \(5(4x - 1)\) oe or [area of triangle] – 10 or [area of rectangle] + 10 oe or [area of triangle] – [area of rectangle] | |
| P1 | for writing a correct equation, eg \(\dfrac{1}{2} \times 8 \times 6x = 5(4x - 1) + 10\) oe or (dep on 1st P1) eg [area of triangle] – 10 = [area of rectangle] or [area of triangle] = [area of rectangle] + 10 or [area of triangle] – [area of rectangle] = 10 | |
| A1 | for 1.25 oe |
Additional guidance
Condone missing brackets for area of rectangle for all process marks