A2 October 2020 Q4
4. A biased coin has a probability \(p\) of landing on heads, where \(0 \lt p \lt 1\)
Simon spins the coin \(n\) times and the random variable \(X\) represents the number of heads.
Taruni spins the coin \(m\) times, \(m \neq n\), and the random variable \(Y\) represents the number of heads.
Simon and Taruni want to combine their results to find unbiased estimators of \(p\).
Simon proposes the estimator \(S = \dfrac{X + Y}{m + n}\) and Taruni proposes \(T = \dfrac{1}{2}\left[\dfrac{X}{n} + \dfrac{Y}{m}\right]\)
| Scheme | Marks | AO |
|---|---|---|
| \(X \sim \mathrm{B}(n, p)\) so \(\mathrm{E}(X) = np\) and \(Y \sim \mathrm{B}(m, p)\) so \(\mathrm{E}(Y) = mp\) | M1 | 3.3 |
| \(\mathrm{E}(S) = \dfrac{\mathrm{E}(X + Y)}{n + m} = \dfrac{np + mp}{n + m} = p\) so \(S\) is unbiased | M1 | 3.4 |
| \(\mathrm{E}(T) = \dfrac{1}{2}\left[\dfrac{\mathrm{E}(X)}{n} + \dfrac{\mathrm{E}(Y)}{m}\right] = \dfrac{1}{2}\left[\dfrac{np}{n} + \dfrac{mp}{m}\right] = \dfrac{1}{2} \times 2p = p\) so \(T\) is unbiased | A1cso | 1.1b |
| (3) |
Notes
1st M1 for selecting correct models for \(X\) and \(Y\)
2nd M1 for using these models to show that either \(S\) or \(T\) is unbiased
A1cso for correctly showing that both are unbiased.
| Scheme | Marks | AO |
|---|---|---|
| \(\mathrm{Var}(S) = \dfrac{np(1-p) + mp(1-p)}{(n+m)^2} = \dfrac{p(1-p)}{n+m}\) | M1 | 2.1 |
| \(\mathrm{Var}(T) = \dfrac{1}{4}\left[\dfrac{np(1-p)}{n^2} + \dfrac{mp(1-p)}{m^2}\right] = \dfrac{p(1-p)(m+n)}{4nm}\) | A1 | 1.1b |
| \(\mathrm{Var}(S) \lt \mathrm{Var}(T) \Rightarrow \dfrac{p(1-p)}{n+m} \lt \dfrac{p(1-p)(m+n)}{4mn} \Leftrightarrow 4mn \lt (n+m)^2\) | M1 | 1.1b |
| \(\Leftrightarrow \quad 0 \lt m^2 + 2mn + n^2 - 4mn \quad \Leftrightarrow \quad 0 \lt (m-n)^2\) So \(S\) always has the smaller variance and is the better estimator | A1cso | 2.2a |
| (4) | ||
| (7 marks) |
Notes
1st M1 for a correct attempt at \(\mathrm{Var}(S)\) or \(\mathrm{Var}(T)\) (need not be simplified)
1st A1 for both correct variances
2nd M1 for a correct inequality in \(m\) and \(n\) and a first step to clear denominators
2nd A1cso for a correct proof and conclusion