A2 June 2023 Q7
7. The random variable \(R\) has a continuous uniform distribution over the interval \([2, 10]\)
A sphere of radius \(R\) cm is formed.
The surface area of the sphere, \(S\) cm2, is given by \(S = 4\pi R^2\)
The volume of the sphere, \(V\) cm3, is given by \(V = \dfrac{4}{3}\pi R^3\)
| Scheme | Marks | AO |
|---|---|---|
| \(\mathrm{f}(r) = \dfrac{1}{8}\) for \(2 \leqslant r \leqslant 10\) [0 otherwise] | B1 | 1.1b |
| (1) |
Notes
B1: correct probability density function with limits
Allow any letter but must be consistent
| Scheme | Marks | AO |
|---|---|---|
| \(\mathrm{E}(4\pi R^2) = 4\pi\mathrm{E}(R^2)\) or \(\displaystyle\int_2^{10} 4\pi r^2\left(\tfrac{1}{8}\right)\mathrm{d}r\) | M1 | 1.1b |
| \(\mathrm{E}(R) = 6\) or \(= \left[\tfrac{1}{2}\pi\left(\dfrac{r^3}{3}\right)\right]_2^{10}\) | M1 | 1.1b |
| \(\mathrm{E}(4\pi R^2) = 4\pi\left(\mathrm{Var}(R) + [\mathrm{E}(R)]^2\right) = 4\pi\left(\tfrac{16}{3} + \text{“}6\text{”}^2\right)\) or \(= \tfrac{1}{2}\pi\left(\dfrac{10^3}{3} - \dfrac{2^3}{3}\right)\) | M1 | 2.1 |
| \(= \dfrac{496\pi}{3}\)* | A1* | 2.2a |
| (4) |
Notes
M1: use of \(\mathrm{E}(aR) = a\mathrm{E}(R)\) / correct integral with their \(\mathrm{f}(r)\) (limits not needed)
M1: \(\mathrm{E}(R) = 6\) seen or implied / use of integration to find \(\mathrm{E}(SA)\)
M1: use of \(\mathrm{E}(R^2) = \mathrm{Var}(R) + [\mathrm{E}(R)]^2\) / correct integration of their \(\mathrm{f}(r)\), limits shown
A1*: exact value from correct working
| Scheme | Marks | AO |
|---|---|---|
| \(\mathrm{E}\left(\tfrac{4}{3}\pi R^3\right) = \displaystyle\int_2^{10} \tfrac{4}{3}\pi r^3\left(\tfrac{1}{8}\right)\mathrm{d}r\) | B1ft | 1.1b |
| \(= \left[\tfrac{1}{6}\pi\left(\dfrac{r^4}{4}\right)\right]_2^{10}\) | M1 | 2.1 |
| \(= \tfrac{1}{6}\pi\left(\dfrac{10^4}{4} - \dfrac{2^4}{4}\right)\) | dM1 | 1.1b |
| \(= 416\pi\) | A1 | 2.2a |
| (4) | ||
| (9 marks) |
Notes
follow through their pdf from (a) for first 3 marks of (c)
B1ft: correct integral for \(\mathrm{E}(V)\) including limits,
M1: integration of their pdf from (a) to find \(\mathrm{E}(V)\)
dM1: (dep on previous M1) use of correct limits, may be implied
A1: \(416\pi\) (allow awrt 1310 to 3 sf)