A2 June 2022 Q4
4. A doctor believes that a four-week exercise programme can reduce the resting heart rate of her patients. She takes a random sample of 7 patients and records their resting heart rate before the exercise programme and again after the exercise programme.
| Patient | \(A\) | \(B\) | \(C\) | \(D\) | \(E\) | \(F\) | \(G\) |
|---|---|---|---|---|---|---|---|
| Resting heart rate before | 65 | 68 | 77 | 79 | 80 | 88 | 92 |
| Resting heart rate after | 63 | 65 | 73 | 76 | 80 | 84 | 80 |
You should state your hypotheses, test statistic and critical value. (7)
| Scheme | Marks | AO |
|---|---|---|
| \(d\): 2 3 4 3 0 4 12 | M1 | 3.1b |
| \(\bar{d} = \pm 4 \qquad s_\mathrm{d} = \sqrt{\tfrac{1}{6}\left(\text{‘}198\text{’} - 7(\text{‘}4\text{’})^2\right)} = \sqrt{14.333\ldots} = 3.7859\ldots\) | M1 | 1.1b |
| \(\mathrm{H}_0 : \mu_\mathrm{d} = 0 \qquad \mathrm{H}_1 : \mu_\mathrm{d} \gt 0\) | B1 | 2.5 |
| \(t = \pm\dfrac{\text{“}\pm 4\text{”}}{\frac{\text{“}3.78\ldots\text{”}}{\sqrt{7}}}\) | M1 | 1.1b |
| \(= \pm 2.795\ldots\) awrt \(\pm 2.80\) | A1 | 1.1b |
| Critical value \(t_6 = \pm 1.943\) | B1 | 1.1b |
| [\(2.80 \gt 1.943\),] therefore there is sufficient evidence to support the doctor’s belief/evidence to suggest resting heart rate is reduced. | A1 | 2.2b |
| (7) |
Notes
M1: For understanding paired \(t\)-test is required and attempting to find differences at least 5 correct, allow \(\pm\) (may be implied by correct \(\bar{d}\) and \(s_\mathrm{d}\))
M1: Complete method for \(\bar{d}\) and \(s_\mathrm{d}\) or \((s_\mathrm{d})^2\)
B1: Correct model for differences with both hypotheses correct in terms of \(\mu\) / \(\mu_\mathrm{d}\) (sign of \(\mathrm{H}_1\) must be compatible with their \(\bar{d}\))
M1: Method for finding test statistic with their values
A1: awrt \(\pm 2.80\) (allow awrt \(\pm 2.8\) from correct working)
B1: Correct critical \(\pm 1.943\) (or better) with compatible sign
A1: Correct comparison to deduce that the doctor’s belief is supported. Must be consistent with their CV and their test statistic (dependent upon all M marks).
SC: Difference of means test apply scheme but also allow 2nd B1 for \(t_{12} = 1.782\)
| Scheme | Marks | AO |
|---|---|---|
| Differences in resting heart rates must be normally distributed for the test to be valid. | B1 | 2.4 |
| (1) | ||
| (8 marks) |
Notes
B1: Correct modelling assumption