June 2018 Paper 3 Q4
4. Charlie is studying the time it takes members of his company to travel to the office. He stands by the door to the office from 08 40 to 08 50 one morning and asks workers, as they arrive, how long their journey was.
Taruni decided to ask every member of the company the time, \(x\) minutes, it takes them to travel to the office.
Taruni’s results are summarised by the box plot and summary statistics below.

Rana and David both work for the company and have both moved house since Taruni collected her data.
Rana’s journey to work has changed from 75 minutes to 35 minutes and David’s journey to work has changed from 60 minutes to 33 minutes.
Taruni drew her box plot again and only had to change two values.
| Scheme | Marks | AO |
|---|---|---|
| Convenience or opportunity [sampling] | B1 | 1.2 |
| (1) |
| Scheme | Marks | AO |
|---|---|---|
| Quota [sampling] | B1 | 1.1a |
| e.g. Take 4 people every 10 minutes | B1 | 1.1b |
| (2) |
Notes
1st B1 for quota (sampling) mentioned (“Stratified” or “systematic” or “random” are B0B0)
2nd B1 for a description of how such a system might work, requires suitable strata or categories
e.g. time slots, departments, gender, age groups, distance travelled etc
Suggestion of randomness is B0
| Scheme | Marks | AO |
|---|---|---|
| Census | B1 | 1.2 |
| (1) |
| Scheme | Marks | AO |
|---|---|---|
| \([58 - 26 =]\ \underline{32}\) (min) | B1 | 1.1b |
| (1) |
| Scheme | Marks | AO |
|---|---|---|
| \(\mu = \dfrac{4133}{95} = 43.505263\ldots\) awrt 43.5 (min) | B1 | 1.1b |
| \(\sigma_x = \sqrt{\dfrac{202\,294}{95} - \mu^2} = \sqrt{236.7026\ldots}\) | M1 | 1.1b |
| \(= 15.385\ldots\) awrt 15.4 (min) | A1 | 1.1b |
| (3) |
Notes
B1 for a correct mean (awrt 43.5)
M1 for a correct expression for the sd (including \(\sqrt{\ }\)) ft their mean
A1 for awrt 15.4 (Allow \(s = 15.4667\ldots\) awrt 15.5)
| Scheme | Marks | AO |
|---|---|---|
| There are outliers in the data (or data is skew) which will affect mean and sd | B1 | 2.4 |
| Therefore use median and IQR | dB1 | 2.4 |
| (2) |
Notes
1st B1 for acknowledging outliers or skewness are a problem for mean and sd
“extreme values”/“anomalies” OK May be implied by saying median and IQR not affected by..
We need to see mention of “outliers”, “skewness” and the problem so “data is skewed so use median and IQR” is B0 unless mention that they are not affected by extreme values or mean and standard deviation can be “inflated” by the positive skew etc
2nd dB1 dep on 1st B1 for therefore choosing median and IQR
| Scheme | Marks | AO |
|---|---|---|
| Value of 20, LQ at 26 and outliers will not change or state that median and upper quartile are the values that do change | B1 | 1.1b |
| More values now below 40 than above so \(Q_2\) or \(Q_3\) will change and be lower | M1 | 2.1 |
| Both \(Q_2\) and \(Q_3\) will be lower | A1 | 2.4 |
| (3) | ||
| (13 marks) |
Notes
B1 for identifying 2 of these 3 groups of unchanged values or stating only \(Q_2\) and \(Q_3\) change
M1 for explaining that median or UQ should be lower.
E.g. the 2 values have moved to below 40 (or 58) and therefore more than 50% below 40 or (more than 75% below 58) or an argument to show that the other 3 values are the same. (o.e.)
Allow arrows on box plot provided statement in words about increased % below 40 or 58 etc
A1 for stating median and UQ are both lower with clear evidence of M1 scored
[If lots of values on 40 then median might not change but, since two values do change then UQ would change. If this meant that 92 became an outlier then we would have a new value for upper whisker and an extra outlier so effectively 3 values are altered. So median changes]