October 2020 Paper 3 Mechanics Q1
1. A rough plane is inclined to the horizontal at an angle \(\alpha\), where \(\tan\alpha = \dfrac{3}{4}\)
A brick \(P\) of mass \(m\) is placed on the plane.
The coefficient of friction between \(P\) and the plane is \(\mu\)
Brick \(P\) is in equilibrium and on the point of sliding down the plane.
Brick \(P\) is modelled as a particle.
Using the model,
For parts (c) and (d), you are not required to do any further calculations.
Brick \(P\) is now removed from the plane and a much heavier brick \(Q\) is placed on the plane.
The coefficient of friction between \(Q\) and the plane is also \(\dfrac{3}{4}\)
Brick \(Q\) is now projected with speed \(0.5\ \text{m s}^{-1}\) down a line of greatest slope of the plane.
Brick \(Q\) is modelled as a particle.
Using the model,
| Scheme | Marks | AO |
|---|---|---|
| Resolve perpendicular to the plane | M1 | 3.4 |
| \(R = mg\cos\alpha = \dfrac{4}{5}mg\) | A1 | 1.1b |
| (2) |
Notes
M1: Correct no. of terms, condone sin/cos confusion
A1: cao with no wrong working seen. \(mg\cos 36.86\) is A0
| Scheme | Marks | AO |
|---|---|---|
| Resolve parallel to the plane or horizontally or vertically | M1 | 3.4 |
| \(F = mg\sin\alpha\) or \(R\sin\alpha = F\cos\alpha\) | A1 | 1.1b |
| Use \(F = \mu R\) and solve for \(\mu\) | M1 | 2.1 |
| \(\mu = \dfrac{3}{4}\) * | A1* | 2.2a |
| (4) |
Notes
M1: Correct no. of terms, condone sin/cos confusion
A1: Correct equation
M1: Must use \(F = \mu R\) (not merely state it) to obtain a numerical value for \(\mu\).
This is an independent M mark.
A1*: Given answer correctly obtained
| Scheme | Marks | AO |
|---|---|---|
| The forces acting on \(Q\) will still balance as the \(m\)’s cancel oe Other possibilities: e.g. the friction will increase in the same proportion as the weight component or force down the plane. The force pulling the brick down the plane increases by the same amount as the friction oe This mark can be scored if they do the calculation. | B1 | 2.4 |
| (1) |
Notes
B1: Must have the 3 underlined phrases/word oe
| Scheme | Marks | AO |
|---|---|---|
| Brick \(Q\) slides down the plane with constant speed. | B1 | 2.4 |
| No resultant force down the plane (so no acceleration) oe | B1 | 2.4 |
| These marks can be scored if they do the calculation. | ||
| (2) | ||
| (9 marks) |
Notes
B1: Must say constant speed.
B1: Any appropriate equivalent statement