June 2025 Paper 2 Q6
6 \(C\) is a point on the straight line \(AB\).
\(AC : CB = 3 : 2\)
Work out the equation of the straight line passing through \(O\) and \(C\). [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(x\)-coordinate of \(C = 11\) | B1 | may be seen on diagram implied by \(C\) (11, …) |
| \(y\)-coordinate of \(C = 6\) | B1 | may be seen on diagram implied by \(C\) (…, 6) |
| \(y = \dfrac{6}{11}x\) | B1ft | oe equation eg \(11y = 6x + 0\) ft their non-zero coordinates of \(C\) |
Additional guidance
| \(C\) (11, 1) \(\quad y = \dfrac{1}{11}x\) | B1B0B1ft |
| \(C\) (3, 6) \(\quad y = \dfrac{6}{3}x\) | B0B1B1ft |
| \(C\) (6, 11) \(\quad y = \dfrac{11x}{6}\) | B0B0B1ft |
| \(C\) (11, 0) \(\quad y = 0\) | B1B0B0ft |
| \(C\) (0, 6) \(\quad y = 6\) | B0B1B0ft |
| Exact equations must be seen for the 3rd B1 eg1 \(C\) (11, 6) \(\quad y = \dfrac{6}{11}x \quad\) Answer \(y = 0.545x\) eg2 \(C\) (11, 6) \(\quad\) Answer \(y = 0.545x \quad \left(y = \dfrac{6}{11}x\right.\) not seen) | B1B1B1 B1B1B0 |
| Condone eg \(C\) (9.5, 3) \(\quad y = \dfrac{3}{9.5}x\) | B0B0B1ft |