June 2022 Paper 1 Q2
2 The point \((-6, -4)\) lies on a straight line with gradient \(\dfrac{3}{2}\)
Work out the coordinates of the point where the line crosses the \(y\)-axis. [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| \(-4 = \dfrac{3}{2} \times -6 + c\) or \(c = 5\) \(y - -4 = \dfrac{3}{2}(x - -6)\) | M1 | oe |
| (0, 5) | A1 | |
| Alternative method 2 | ||
| Correctly adding at least 1 multiple of 2 to the right and 3 up eg \(-6 + 2 = -4\) and \(-4 + 3 = -1\) | M1 | oe needs to be added to both vertical and horizontal. Could be seen in coordinates eg \((-4, -1)\) could be 1 right and 1.5 up or \(y\) coordinate of \(-4 + 1.5 \times 6\) |
| (0, 5) | A1 | |
| Alternative method 3 | ||
| Sketch drawn with straight line passing through \((-6, -4)\) and (0, 5) with steps shown | M1 | just a line passing through 5 seen on the axis is enough for M1 but won’t gain A1 unless written as coordinates |
| (0, 5) | A1 | answer could be embedded in diagram |
Additional guidance
| (0, 5) seen without working will be 2 marks | M1A1 |