June 2022 Paper 1 Q13
13 Simplify fully \(\quad (6x^3y^{-2} + 9x^5y) \div 3x^2y^{-3}\) [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| 2 and 3 | B1 | coefficients |
| \(x\) and \(x^3\) | B1 | |
| \(y\) and \(y^4\) | B1 |
Additional guidance
| \(2xy + 3x^3y^4\) or \(xy(2 + 3x^2y^3)\) scores B3 If no B marks awarded then \(3x^3(2y^{-2} + 3x^2y)\) or \(3x^3y(2y^{-3} + 3x^2)\) or \(3x^3y^{-2}(2 + 3x^2y^3)\) or \(3x^2(2xy^{-2} + 3x^3y)\) or \(3x^2y(2xy^{-3} + 3x^3)\) or \(3x^2y^{-2}(2x + 3x^3y^3)\) seen in the working for the numerator Penalise incorrect further working for the B marks | B3 SC1 |