June 2019 Paper 1 Q3
3 Work out the smallest integer value of \(x\) that satisfies the inequality \(\quad 8 - 5x \lt 26\) [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(-18 \lt 5x\) or \(8 - 26 \lt 5x\) or \(-5x \lt 26 - 8\) or \(-5x \lt 18\) or \(x \gt -3.6\) or \(-x \lt 3.6\) | M1 | \(5x\) or \(x\) term isolated on one side of a correct inequality |
| \(-3\) | A1 |
Additional guidance
| Trial and improvement (with no incorrect working) with correct answer. Could be as little as one trial | M1, A1 |
| Trial and improvement with incorrect answer or choice | M0, A0 |
| \(-5x \lt 18\) but \(x \lt -3.6\) (error) answer \(-3\) (common double error, answer should be \(-4\) following the first error) | M1, A0 |
| \(8 - 5x = 26\) leading to \(x = -3\) | M1, A1 |
| \(8 - 5x = 26\) not leading to \(x = -3\) | M0, A0 |