Higher November 2024 Paper 1 Q15
15
(a) Solve the inequality \(\quad 20 - 5x \leqslant 30\) [3 marks]
(b) Represent \(\quad x \gt -1 \quad\) on the number line. [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| Correct rearrangement with \(-5x\) the subject or \(5x\) positive or correct division throughout by 5 | M1 | eg \(-5x \leqslant 30 - 20\) or \(-5x \leqslant 10\) or \(20 \leqslant 30 + 5x\) or \(20 - 30 \leqslant 5x\) or \(-10 \leqslant 5x\) or \(4 - x \leqslant 6\) |
| Correct rearrangement with \(-x\) the subject or \(x\) positive | M1dep | eg \(-x \leqslant 10 \div 5\) or \(-x \leqslant 2\) or \(10 \div 5 \geqslant -x\) or \(2 \geqslant -x\) or \(x \geqslant 10 \div -5\) or \(x \geqslant -\dfrac{10}{5}\) or \(-10 \div 5 \leqslant x\) or \(-\dfrac{10}{5} \leqslant x\) or \(4 \leqslant 6 + x\) |
| \(x \geqslant -2\) or \(-2 \leqslant x\) | A1 | SC1 for answer \(-2\), which may be seen in an equation or incorrect inequality |
Additional guidance
Allow incorrect signs in working if recovered in final answer
Allow \(\lt\) for \(\leqslant\) or \(\gt\) for \(\geqslant\) for method marks
Unless recovered, use of = scores maximum SC1
| Answer | Mark | Comments |
|---|---|---|
Hollow circle at \(-1\) with an arrow to the right | B1 | mark intention circle and arrow can be above, on or below the line |