Higher November 2022 Paper 2 Q28
28 ABCDEF is a triangular prism.
P is a point on EF.
\(EB = 29\) cm
Angle \(EBP = 35^\circ\)
Angle \(EPB = 114^\circ\)
Work out the length of \(EP\). [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(\dfrac{EP}{\sin 35} = \dfrac{29}{\sin 114}\) or \(\dfrac{29 \sin 35}{\sin 114}\) | M1 | oe eg \(\dfrac{\sin 35}{EP} = \dfrac{\sin 114}{29}\) or \(\dfrac{EP}{\sin 35} =\) [31.7, 31.7445] |
| [18.2, 18.21] | A1 | accept 18 with M1 scored |
Additional guidance
\(EP\) may be \(PE\) or \(x\) etc
Do not regard 31 as a misread of 35