Higher November 2019 Paper 3 Q18
18 Work out the two roots of \(\quad (7x + 1)(2x - 3) = 0\)
Circle both roots. [1 mark]
- \(-\dfrac{1}{7}\)
- \(\dfrac{1}{7}\)
- \(-\dfrac{3}{2}\)
- \(\dfrac{3}{2}\)
| Answer | Mark | Comments |
|---|---|---|
| \(-\dfrac{1}{7}\) and \(\dfrac{3}{2}\) | B1 |