Higher November 2019 Paper 1 Q22
22 (−3, 10) is a point on line L.
(4, 0) and (6, 10) are points on line M.
L and M are parallel.
Not drawn accurately
Work out the equation of line L.
Give your answer in the form \(\quad y = mx + c\) [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(\dfrac{10 - 0}{6 - 4}\) or \((m =)\ \dfrac{10}{2}\) or \(-3 - (6 - 4)\) or \(-3 - 2\) or \(4 - (6 - (-3))\) or \(-5\) or \((-5, 0)\) and \(\dfrac{10 - 0}{-3 - (-5)}\) or \((m =)\ \dfrac{10}{2}\) or \(0 = 4m + k\) and \(10 = 6m + k\) and \(10 - 0 = 6m - 4m\) or \(2m = 10\) or \((m =)\ 5\) | M1 | oe method to find the gradient of either line implied by \(y = 5x \ldots\) any letters |
| \(10 =\) their \(5 \times (-3) + c\) or \((c =)\ 5 \times (6 - (-3)) - 20\) or \((c =)\ 25\) or \(y - 10 =\) their \(5(x - (-3))\) or \(y = 5(x + 9) - 20\) or \(5x + 25\) | M1dep | oe |
| \(y = 5x + 25\) | A1 |
Additional guidance
| Do not allow further incorrect work, eg \(y = 5x + 25\) and then \(y = x + 5\) | M1M1A0 |