Higher November 2018 Paper 3 Q10
10 Solve \(\quad 8 > 3 - \dfrac{1}{2}x\) [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| \(\dfrac{1}{2}x > 3 - 8\) or \(\dfrac{1}{2}x > {-5}\) or \(8 - 3 > -\dfrac{1}{2}x\) or \(5 > -\dfrac{1}{2}x\) or \(8 + \dfrac{1}{2}x > 3\) | M1 | oe |
| \(x > {-10}\) | A1 | oe \(-10 < x\) |
| Alternative method 2 | ||
| \(16 > 6 - x\) or \(16 - 6 > -x\) or \(10 > -x\) or \(x > 6 - 16\) or \(16 + x > 6\) | M1 | oe |
| \(x > {-10}\) | A1 | oe \(-10 < x\) |
Additional guidance
| Answer using incorrect sign eg \(x < {-10}\) or \(x = {-10}\) | M1A0 |