Higher November 2017 Paper 3 Q8
8
ABCD is a parallelogram.\(AB = BP\)
Not drawn accurately
Work out the size of angle \(x\). [4 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| \(PAB = 51\) or \(PAD = 51\) or \(APC = 180 - 51\) or \(APC = 129\) | M1 | |
| \(ABP = 180 - 51 -\) their 51 or \(ABP = 180 - 102\) or \(ABP = 78\) or \(ADC = 180 -\) their 51 \(-\) their 51 \(ADC = 180 - 102\) \(ADC = 78\) | M1dep | \(PAB = 51\) and \(PAD = 51\) or \(BAD = 102\) |
| \(BCD = 180 -\) their 78 or \(BCD = 360 -\) their 129 \(-\) their 51 \(-\) their 78 or \(BCD = 360 - 258\) or \(BCD = 102\) or \(4x = 180 -\) their 78 or \(4x = 360 -\) their 129 \(-\) their 51 \(-\) their 78 or \(4x = 360 - 258\) or \(4x = 102\) or \(102 \div 4\) | M1dep | oe eg \(BCD = (360 - 2 \times \text{their } 78) \div 2\) or \(4x = (360 - 2 \times \text{their } 78) \div 2\) |
| 25.5 | A1 | |
| Alternative method 2 | ||
| \(ABC = 180 - 3x - x\) or \(ABC = 180 - 4x\) or \(APC = 180 - 51\) or \(APC = 129\) | M1 | |
| \(PAB = 2x\) or \(APB = 2x\) or \(2x = 51\) | M1dep | |
| \(51 \div 2\) | M1dep | |
| 25.5 | A1 | |
Additional guidance
Angles must be labelled or shown on diagram