Higher November 2017 Paper 2 Q3
3 Circle the point that does not lie on the curve \(\quad y = x^3\) [1 mark]
- \(\left(-\dfrac{1}{2}, -\dfrac{1}{8}\right)\)
- (5, 125)
- \(\left(\dfrac{1}{3}, \dfrac{1}{9}\right)\)
- (−1, −1)
| Answer | Mark | Comments |
|---|---|---|
| \(\left(\dfrac{1}{3}, \dfrac{1}{9}\right)\) | B1 |