Higher June 2024 Paper 3 Q22
22 Fatima is choosing a 4-digit code.
Each digit is a whole number from 0 to 9
She decides
- all her digits will be odd numbers
- no digits will be repeated.
How many different codes can she make? [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(5\ (\times)\ 4\ (\times)\ 3\ (\times)\ 2\) | M1 | oe |
| 120 with no errors in working | A1 | SC1 625 (allowing repeated digits) |
Additional guidance
| Ignore any listing of possible codes | |
| Condone further working after 120 seen and M1 awarded eg answer as a probability \(\dfrac{1}{120}\) | M1A1 |
| 5, 4, 3, 2 | M1A0 |
| 5, 4, 3, 2, 1 or \(5 \times 4 \times 3 \times 2 \times 1 = 120\) | M0A0 |