Higher June 2019 Paper 1 Q19

AQACurrent spec1 markRecurring Decimals

19 Circle the fraction that is equivalent to \(\quad 0.\dot{1}\) [1 mark]

  • \(\dfrac{1}{9}\)
  • \(\dfrac{1}{99}\)
  • \(\dfrac{1}{10}\)
  • \(\dfrac{11}{100}\)