Higher June 2018 Paper 1 Q5
5 Solve \(\quad 5(x + 3) \lt 60\) [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(5x + 15 \lt 60\) or \(5x \lt 45\) or \(x + 3 \lt 12\) | M1 | |
| \(x \lt 9\) or \(9 \gt x\) | A1 | SC1 incorrect sign eg \(x \leqslant 9\) or \(x = 9\) or \(x \gt 9\) or \(x \geqslant 9\) or \(x = \lt 9\) or answer of 9 |
Additional guidance
| Allow use of other inequality signs or \(=\) if recovered to answer of \(x \lt 9\) | M1A1 |
| Embedded answer of \(5(9 + 3) \lt 60\) | M0A0 |
| \(5x + 3 \lt 60\) followed by \(x + 3 \lt 12\) followed by \(x \lt 9\) is not a recovery, but is two errors | M0A0 |