Foundation November 2023 Paper 2 Q4
4
(a) Solve \(\quad \dfrac{x}{3} = 6\) [1 mark]
(b) Solve \(\quad 2x + 3 = 27\) [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| 18 | B1 |
Additional guidance
| Embedded answer with no or incorrect answer eg \(\dfrac{18}{3} = 6\) | B0 |
| Answer | Mark | Comments |
|---|---|---|
| \(2x = 27 - 3\) or \(2x = 24\) or \(\dfrac{27 - 3}{2}\) or \(\dfrac{24}{2}\) or \(x + 1.5 = 13.5\) | M1 | oe eg \(2x + 3 = 27\) then \(-3\) from both sides or \(-2x = 3 - 27\) or \(-2x = -24\) |
| 12 | A1 |
Additional guidance
| Embedded answer with no or incorrect answer eg \(2 \times 12 + 3 = 27\) without 12 selected or with incorrect answer | M1A0 |
| Trial and improvement with answer 12 | M1A1 |
| Trial and improvement with no answer or answer other than 12 | M0A0 |