Foundation November 2019 Paper 2 Q22
22 Here is a cuboid.
The two largest faces are blue.
The other four faces are green.
Is the total blue area greater than the total green area?
You must show your working. [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(9 \times 5\) or 45 or \(9 \times 3\) or 27 or \(5 \times 3\) or 15 | M1 | may be multiplied by 2 implied by 90 or 54 or 30 or (total =) 174 or 90 + 54 + 30 = 174 |
| \(9 \times 5 \times 2\) or 90 and \(9 \times 3 \times 2 + 5 \times 3 \times 2\) or \(54 + 30\) or 84 or \(9 \times 5\) or 45 and \(9 \times 3 + 5 \times 3\) or \(27 + 15\) or 42 | M1dep | accept blue = 90 and (total =) 174 or green = 84 and (total =) 174 |
| 90 and 84 and Yes or 45 and 42 and Yes | A1 | oe condone incorrect units |
Additional guidance
| Yes may be seen by the question or implied by eg blue is bigger | |
| Ticking or circling blue or 90 without a comment does not imply Yes | |
| Allow M1 even if not subsequently used | |
| Allow M1 even if seen among other calculations for eg perimeter or volume | |
| Works out the area of a face and then uses this for the ‘volume’ eg \(5 \times 3 = 15\), \(15 \times 9 = 135\) or \(5 \times 3 = 15\), \(15 \times 15 = 225\) | M1M0A0 |
| Only works out a ‘volume’ with correct or incorrect method eg \(5 \times 3 \times 9 = 135\) or \(5 \times 3 \times 5 \times 3 = 225\) | M0M0A0 |
| Ignore incorrect subtraction eg 90, 84 and Yes blue is 8 greater | M1M1A1 |
| 90 + 54 + 30 = 174 \((174 \div 2 = 87)\) 90 is more than half so Yes or 84 is less than half so Yes | M1 M1A1 |
| Only 90 and 174 without identifying 90 as the blue area | M1M0A0 |