Foundation November 2019 Paper 1 Q21
21 Solve \(\quad 8x + 7 = 2x + 10\) [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(\pm 6x\) or \(\pm 3\) or \(8x - 2x = 10 - 7\) or \(7 - 10 = 2x - 8x\) | M1 | oe terms in \(x\) or constant terms collected |
| \(6x = 3\) or \(-6x = -3\) | A1 | oe implied by correct answer |
| 0.5 or \(\dfrac{1}{2}\) | A1ft | oe eg \(\dfrac{3}{6}\) ft any equation of form \(6x = a\) or \(-6x = a\) or \(bx = 3\) or \(bx = -3\) |
Additional guidance
| \(\dfrac{-3}{-6}\) | M1A1A0 |
| Trial and Improvement scores 0 or 3 |