Foundation November 2017 Paper 3 Q22
22 ABCD is a parallelogram.
AB = BP
Not drawn accurately
Work out the size of angle \(x\). [4 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 of 2 | ||
| PAB = 51 or PAD = 51 or APC = 180 – 51 or APC = 129 | M1 | |
| ABP = 180 – 51 – their 51 or ABP = 180 – 102 or ABP = 78 or ADC = 180 – their 51 – their 51 ADC = 180 – 102 ADC = 78 | M1dep | PAB = 51 and PAD = 51 or BAD = 102 |
| BCD = 180 – their 78 or BCD = 360 – their 129 – their 51 – their 78 or BCD = 360 – 258 or BCD = 102 or \(4x\) = 180 – their 78 or \(4x\) = 360 – their 129 – their 51 – their 78 or \(4x\) = 360 – 258 or \(4x\) = 102 or \(102 \div 4\) | M1dep | oe eg BCD = (360 – 2 \(\times\) their 78) \(\div\) 2 or \(4x\) = (360 – 2 \(\times\) their 78) \(\div\) 2 |
| 25.5 | A1 | |
| Alternative method 2 of 2 | ||
| ABC = 180 – \(3x - x\) or ABC = 180 – \(4x\) or APC = 180 – 51 or APC = 129 | M1 | |
| PAB = \(2x\) or APB = \(2x\) or \(2x = 51\) | M1dep | |
| \(51 \div 2\) | M1dep | |
| 25.5 | A1 | |
Additional guidance
Angles must be labelled or shown on the diagram