Foundation November 2017 Paper 3 Q17

17 Circle the equation which has the solution \(\qquad x = 6\) [1 mark]

• \(x - 3 = \dfrac{x}{2}\)
• \(x = \dfrac{3 + x}{2}\)
• \(3x = 36\)
• \(\dfrac{x}{6} = 0\)