Foundation June 2022 Paper 2 Q17
17
(a) \(x\) is at least 7
Circle the correct inequality. [1 mark]
- \(x \lt 7\)
- \(x \leqslant 7\)
- \(x \gt 7\)
- \(x \geqslant 7\)
(b) Multiply out \(5c(2d + 1)\) [2 marks]
(c) Factorise \(21x + 28\) [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| \(x \geqslant 7\) | B1 |
| Answer | Mark | Comments |
|---|---|---|
| \(10cd + 5c\) or \(10dc + 5c\) or \(5c + 10cd\) or \(5c + 10dc\) | B2 | B1 fully simplified first term ie \(10cd\) or \(10dc\) or correct expansion not fully simplified eg \(10 \times cd + 5c\) or \(5c \times 2d + 5c\) (\(\times\) 1) or \(5c2d + 5 \times c\) |
Additional guidance
| Further incorrect work after a B2 response is B1 eg \(10cd + 5c = 15cd\) | B1 |
| Further incorrect work after a B1 response is still B1 eg \(10cd + 1 = 11cd\) | B1 |
| Answer | Mark | Comments |
|---|---|---|
| \(7(3x + 4)\) | B1 |
Additional guidance
| Condone missing final bracket ie \(7(3x + 4\) | B1 |
| Allow multiplying back out to check their answer | |
| Further incorrect work after a correct response is B0 eg \(7(3x + 4) = 7(7x)\) | B0 |
| \(7(x3 + 4)\) | B0 |
| \(7 \times (3x + 4)\) | B0 |