Foundation June 2018 Paper 1 Q10
10 Here is a list of numbers.
\[5 \qquad 6 \qquad 1 \qquad 3 \qquad 5 \qquad 5 \qquad 8 \qquad 4 \qquad 2 \qquad 2\](a) Work out the median. [2 marks]
(b) Work out the mean. [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| Orders the numbers to at least the sixth number from either end 1 2 2 3 4 5 (\(\ldots\ \ldots\ \ldots\ \ldots\)) or 8 6 5 5 5 4 (\(\ldots\ \ldots\ \ldots\ \ldots\)) or 4 and 5 indicated or \(\dfrac{4 + 5}{2}\) | M1 | (\(\ldots\ \ldots\ \ldots\ \ldots\)) 5 4 3 2 2 1 or (\(\ldots\ \ldots\ \ldots\ \ldots\)) 4 5 5 5 6 8 |
| 4.5 with no errors in working | A1 | oe eg \(4\dfrac{1}{2}\) |
Additional guidance
| 4/5 | M1A0 |
| 4,5 (cannot accept as 4.5) | M1A0 |
| Allow 4 and 5 to be the only ones not crossed out as ‘4 and 5 indicated’ | M1 |
| eg 1 2 2 3 4 5 5 6 6 8 and answer 4.5 (error in ordering) | M1A0 |
| eg 1 2 3 3 4 5 5 5 6 8 and answer 4.5 (error in ordering) | M1A0 |
| Ignore any \(+\) signs between ordered values unless the total is then calculated and used in this part |
| Answer | Mark | Comments |
|---|---|---|
| \((5 + 6 + 1 + 3 + 5 + 5 + 8 + 4 + 2 + 2) \div 10\) or \(41 \div 10\) | M1 | Allow one value omitted or incorrect if method clear |
| 4.1 or \(4\dfrac{1}{10}\) | A1 |
Additional guidance
| Answer of 4 with correct working or 4.1 seen | M1A1 |
| Answer of 4 without correct working and without 4.1 seen | M0A0 |
| Condone missing first and/or final bracket for M1 | |
| If their total is not 41, all additions must be shown or implied eg they write \(5 + \ldots + 2 = 42\) and \(42 \div 10\) eg they write \(5 + 6 + 1 +\) etc \(= 24\) and \(24 \div 10\) (both clearly implying that they are adding up all the numbers – minimum is two of the values shown as being added) | M1A0 |
| but, for example, \(42 \div 10\) (no other working) | M0 |
| Method mark could be scored for work at top of page, above, but not in, part (a) It cannot be assumed that work done in part (a) is intended for part (b) | |
| Answer of \(\dfrac{41}{10}\) or \(\dfrac{4.1}{1}\) or 4 r(emainder) 1 | M1A0 |