AS June 2024 Paper 1 Q4

4 The line \(L\) has vector equation

\[\mathbf{r} = \begin{bmatrix} 4 \\ -7 \\ 0 \end{bmatrix} + \lambda\begin{bmatrix} -9 \\ 1 \\ 3 \end{bmatrix}\]

Give the equation of \(L\) in Cartesian form.

Tick (✓) one box. [1 mark]

• \(\dfrac{x + 4}{-9} = \dfrac{y - 7}{1} = \dfrac{z}{3}\)
• \(\dfrac{x - 4}{-9} = \dfrac{y + 7}{1} = \dfrac{z}{3}\)
• \(\dfrac{x + 9}{4} = \dfrac{y - 1}{-7}\), \(z = 3\)
• \(\dfrac{x - 9}{4} = \dfrac{y + 1}{-7}\), \(z = 3\)