A2 June 2022 Paper 2 Q3
3 The roots of the equation \(x^2 - px - 6 = 0\) are \(\alpha\) and \(\beta\)
Find \(\alpha^2 + \beta^2\) in terms of \(p\)
Circle your answer. [1 mark]
- \(p^2 - 6\)
- \(p^2 + 6\)
- \(p^2 - 12\)
- \(p^2 + 12\)
| Scheme | Marks | AO |
|---|---|---|
| Circles correct answer | B1 | 1.1b |
| (1 mark) |