A2 June 2020 Paper 2 Q3

AQACurrent spec1 markDifferentiation & Maclaurin

3 Find the gradient of the tangent to the curve

\[y = \sin^{-1} x\]

at the point where \(x = \dfrac{1}{5}\)

Circle your answer. [1 mark]

  • \[\frac{5\sqrt{6}}{12}\]
  • \[\frac{2\sqrt{6}}{5}\]
  • \[\frac{4\sqrt{3}}{25}\]
  • \[\frac{25}{24}\]