A2 June 2019 Paper 2 Q6

AQACurrent spec6 marksComplex Numbers

6 A circle \(C\) in the complex plane has equation \(|z - 2 - 5\mathrm{i}| = a\)

The point \(z_1\) on \(C\) has the least argument of any point on \(C\), and \(\arg(z_1) = \dfrac{\pi}{4}\)

Prove that \(a = \dfrac{3\sqrt{2}}{2}\) [6 marks]