IMC 2006 Q1
1. What fraction is half-way between \(\dfrac{1}{4}\) and \(\dfrac{1}{6}\) ?
- A \(\dfrac{1}{10}\)
- B \(\dfrac{2}{9}\)
- C \(\dfrac{5}{24}\)
- D \(\dfrac{3}{14}\)
- E \(\dfrac{7}{12}\)
Intermediate Mathematical Challenge 2006, Question 1. © UK Mathematics Trust. Original paper on ukmt.org.uk
Answer: C \(\dfrac{5}{24}\)
Note that \(\dfrac{1}{4} = \dfrac{6}{24}\) and \(\dfrac{1}{6} = \dfrac{4}{24}\). So \(\dfrac{5}{24}\) is half-way between them.
Solution © UK Mathematics Trust, from the IMC 2006 solutions.