IMC 2004 Q10
10. What is the mean of \(\dfrac{1}{2}, \dfrac{1}{3}, \dfrac{1}{4}\) and \(\dfrac{1}{6}\)?
- A \(\dfrac{1}{5}\)
- B \(\dfrac{1}{15}\)
- C \(\dfrac{5}{12}\)
- D \(\dfrac{7}{24}\)
- E \(\dfrac{5}{16}\)
Intermediate Mathematical Challenge 2004, Question 10. © UK Mathematics Trust. Original paper on ukmt.org.uk
Answer: E \(\dfrac{5}{16}\)
The four fractions total \(\dfrac{5}{4}\), so their mean = \(\dfrac{5}{4} \div 4 = \dfrac{5}{16}\).
Solution © UK Mathematics Trust, from the IMC 2004 solutions.