(Perpendicular height is) h = 1.658(...m) or 1.66 (m) or 1.7 (m)
A1
Accept √11 ⁄ 2 Do not accept truncation to 1.6(m) or 1.65 (m) (But FT allowed) FT from M1, A0 for the correctly evaluated square root of ‘their 2.75’ provided ‘their answer’ <1.8 (m)
(Volume of Luned’s tent =) ½ × (0.7+0.7) × 1.658.... × 2.5 or equivalent
M1
FT ‘their derived 1.658(....)’ provided ≠1.8 or ≠0.7
(Volume) Answer in the inclusive range 2.9 (m3) to 2.98(m3) or 3(.0m3)
A1
Check from correct working (in particular for an answer of 3(m3)) FT 1.6m or 1.65m to an answer in the range 2.8(m3) to 2.89(m3) FT from previous M1 awarded for a similar range
We'd like to use Google Analytics cookies to count visits and see which pages help most. They're optional, and the site works exactly the same either way. Privacy policy