Intermediate November 2018 Unit 2 Q10
10.
(a) A number is decreased by 12% of its value.
This is done 3 times, each time decreasing the previous value by 12%.
Circle the multiplier that you would use to find the value after the 3 decreases. [1]
This is done 3 times, each time decreasing the previous value by 12%.
Circle the multiplier that you would use to find the value after the 3 decreases. [1]
\(\times\, 0{\cdot}36\) \(\times\, 0{\cdot}88^{3}\) \(\times\, 0{\cdot}12^{3}\) \(\times\, 0{\cdot}3^{12}\) \(\times\, 0{\cdot}3^{88}\)
(b) Calculate the percentage change when 42·5 is increased to 45·9. [3]
| Scheme | Marks | Comments |
|---|---|---|
| × 0·883 | B1 |
| Scheme | Marks | Comments |
|---|---|---|
| \(\dfrac{45{\cdot}9 - 42{\cdot}5}{42{\cdot}5}\) (= 0·08) OR \(\dfrac{45{\cdot}9}{42{\cdot}5}\) (= 1·08) | M1 | May be seen in parts. |
| 0·08 × 100 OR (1·08 × 100) – 100 | m1 | |
| 8(%) | A1 | C.A.O. If no marks awarded allow SC1 for −8(%). |